Given a binary tree, find its maximum depth.
The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.
貌似没啥好讲的~直接上代码吧。
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int maxDepth(TreeNode* root) {
//这个Max保存的是root结点下左右子树的最大深度
int max = 0;
//如果root为空说明是个空树
if(root == NULL)
return max;
//root不为空就检查左右子树的深度,返回左右子树中的最大深度+root自身占用的一层 ==带上root这棵树总共多少层
if(root!= NULL)
{
int leftDepth = 0;
int rightDepth = 0;
if(root->right != NULL)
{
rightDepth = maxDepth(root->right);
}
if(root->left != NULL)
{
leftDepth = maxDepth(root->left);
}
max = leftDepth>rightDepth ? leftDepth:rightDepth;
}
return max+1;
}
};
结果: