Balloon Comes!

Problem Description The contest starts now! How excited it is to see balloons floating around. You, one of the best programmers in HDU, can get a very beautiful balloon if only you have solved the very very very... easy problem. Give you an operator (+,-,*, / --denoting addition, subtraction, multiplication, division respectively) and two positive integers, your task is to output the result.  Is it very easy?  Come on, guy! PLMM will send you a beautiful Balloon right now! Good Luck!

Input Input contains multiple test cases. The first line of the input is a single integer T (0<T<1000) which is the number of test cases. T test cases follow. Each test case contains a char C (+,-,*, /) and two integers A and B(0<A,B<10000).Of course, we all know that A and B are operands and C is an operator.

Output For each case, print the operation result. The result should be rounded to 2 decimal places If and only if it is not an integer.

Sample Input 4 + 1 2 - 1 2 * 1 2 / 1 2

Sample Output 3 -1 2 0.50

#include <iostream>
#include <stdio.h>

using namespace std;

int main(){
	int T;
	cin >> T;
	/*char c;
	int a, b;*/
	while (T--){
		char c;
		
		int a, b;
		
		cin >> c >> a >> b;
		if (c == '+'){
			cout << a + b << endl;
		}
		else if (c == '-'){
			cout<< a - b << endl;
		}
		else if (c == '*'){
			cout<< a * b <<endl;
		}
		else if(c == '/'){
			if (a%b == 0){
				cout << a / b << endl;     //注意这里要看清题意 
			}
			else
				printf("%.2f\n", (float)a/b);      //这里我第一次 float（a/b）,这2个是不一样的
		}
	}
	
	return 0;
}