distribute candies

解决一个整数数组中的糖果分配问题,确保兄妹两人能平分不同种类的糖果,目标是最大化妹妹能够获得的不同种类糖果的数量。

Given an integer array with even length, where different numbers in this array represent different kinds of candies. Each number means one candy of the corresponding kind. You need to distribute these candies equally in number to brother and sister. Return the maximum number of kinds of candies the sister could gain.

Example 1:

Input: candies = [1,1,2,2,3,3]
Output: 3
Explanation:
There are three different kinds of candies (1, 2 and 3), and two candies for each kind.
Optimal distribution: The sister has candies [1,2,3] and the brother has candies [1,2,3], too. 
The sister has three different kinds of candies. 

Example 2:

Input: candies = [1,1,2,3]
Output: 2
Explanation: For example, the sister has candies [2,3] and the brother has candies [1,1]. 
The sister has two different kinds of candies, the brother has only one kind of candies. 

Note:

  1. The length of the given array is in range [2, 10,000], and will be even.
  2. The number in given array is in range [-100,000, 100,000].


尝试:


class Solution {
public:
    int distributeCandies(vector<int>& candies) {
                    vector<int> num;
                 for(i=0;i<num.size();i++)
                 {
                      if (num[i])
                 }
                   
        
    }
};




显然不对,不需要重新定义。



修改:


class Solution {
    
public:
    int distributeCandies(vector<int>& candies) {
                    int num=0;
               sort(candies.begin(),candies.end());
          for (int i=0;i<candies.size();i++)
                 {
                      if (candies[i]!=candies[i+1])
                          num+=1;
                 }
                   if(candies.size()/2.0<=num)
                   { 
                     
                       return  candies.size()/2.0;
                   }
                    
                      else 
                      {
                          return num;   
                    }
               }
           };




报错,从o开始到最后一个不对啊!(i+1)

class Solution {
    
public:
    int distributeCandies(vector<int>& candies) {
                    int num=1;
               sort(candies.begin(),candies.end());
          for (int i=0;i<candies.size()-1;i++)
                 {
                      if (candies[i]!=candies[i+1])
                          num+=1;
                 }
                   if(candies.size()/2.0<=num)
                   { 
                     
                       return  candies.size()/2.0;
                   }
                    
                      else 
                      {
                          return num;   
                    }
               }
           };


Problem Statement You have an unlimited supply of two types of candies: small candies and large candies. The weight of a small candy is X grams, and the weight of a large candy is Y grams. Large candies are heavier than small candies (that is, X<Y). There are N children, numbered 1 to N. You have decided to distribute candies so that the following conditions are satisfied: For i=1,…,N, child i receives exactly A i ​ candies in total of the two types. The total weights of candies distributed to the N children are all equal. Determine whether there exists a distribution method that satisfies the conditions. If it exists, find the maximum possible value for the number of large candies distributed. DeepL 翻译    问题陈述 你有无限量的两种糖果:小糖果和大糖果。小糖果的重量是 X 克,大糖果的重量是 Y 克。大糖果比小糖果重(即 X<Y )。 有 N 个孩子,编号为 1 至 N 。 你决定分发糖果,以满足以下条件: 对于 i=1,…,N 来说, i 个孩子收到的两种糖果的总重量正好是 A i ​ 。 分给 N 个孩子的糖果的总重量都相等。 确定是否存在满足条件的分配方法。如果存在,求大号糖果分配数量的最大可能值。    Constraints 2≤N≤2×10 5 1≤A i ​ ≤10 9 1≤X<Y≤10 9 All input values are integers. DeepL 翻译    限制因素 2≤N≤2×10 5 1≤A i ​ ≤10 9 1≤X<Y≤10 9 所有输入值均为整数。    Input The input is given from Standard Input in the following format: N X Y A 1 ​ … A N ​ DeepL 翻译    输入 输入内容由标准输入法提供,格式如下 N X Y A 1 ​ … A N ​    Output If there is no distribution method that satisfies the conditions, output -1. If there exists a distribution method that satisfies the conditions, output the maximum possible value for the number of large candies distributed in such a distribution method. DeepL 翻译    输出 如果没有满足条件的分配方法,则输出 -1。 如果存在满足条件的分配方法,则输出这种分配方法所分配的大颗糖果数量的最大可能值。
最新发布
11-16
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