Description
可支持插入、删除、求最大异或值的线性基。
Solution
插入、求最大异或值都比较基础。
其实删除也是套路吧,,直接建一棵时间线段树即可。
Code
/************************************************
* Au: Hany01
* Date: Apr 5th, 2018
* Prob: [BZOJ4184] shallot
* Email: hany01@foxmail.com
************************************************/
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
typedef pair<int, int> PII;
#define File(a) freopen(a".in", "r", stdin), freopen(a".out", "w", stdout)
#define rep(i, j) for (register int i = 0, i##_end_ = (j); i < i##_end_; ++ i)
#define For(i, j, k) for (register int i = (j), i##_end_ = (k); i <= i##_end_; ++ i)
#define Fordown(i, j, k) for (register int i = (j), i##_end_ = (k); i >= i##_end_; -- i)
#define Set(a, b) memset(a, b, sizeof(a))
#define Cpy(a, b) memcpy(a, b, sizeof(a))
#define x first
#define y second
#define pb(a) push_back(a)
#define mp(a, b) make_pair(a, b)
#define ALL(a) (a).begin(), (a).end()
#define SZ(a) ((int)(a).size())
#define INF (0x3f3f3f3f)
#define INF1 (2139062143)
#define Mod (1000000007)
#define debug(...) fprintf(stderr, __VA_ARGS__)
#define y1 wozenmezhemecaia
template <typename T> inline bool chkmax(T &a, T b) { return a < b ? a = b, 1 : 0; }
template <typename T> inline bool chkmin(T &a, T b) { return b < a ? a = b, 1 : 0; }
inline int read()
{
register int _, __; register char c_;
for (_ = 0, __ = 1, c_ = getchar(); c_ < '0' || c_ > '9'; c_ = getchar()) if (c_ == '-') __ = -1;
for ( ; c_ >= '0' && c_ <= '9'; c_ = getchar()) _ = (_ << 1) + (_ << 3) + (c_ ^ 48);
return _ * __;
}
const int maxn = 500005;
int n, Ans[maxn];
vector<int> vct[maxn << 2];
map<int, PII> pos;
struct LinearBasis
{
int a[31];
inline void insert(int x) {
Fordown(i, 30, 0) if (x >> i & 1) {
if (!a[i]) { a[i] = x; return ; }
else x ^= a[i];
}
}
inline int getans()
{
register int ans = 0;
Fordown(i, 30, 0) chkmax(ans, ans ^ a[i]);
return ans;
}
}base[40];
#define lc (t << 1)
#define rc (lc | 1)
#define mid ((l + r) >> 1)
void update(int t, int l, int r, int x, int y, int dt)
{
if (x <= l && r <= y) {
vct[t].pb(dt);
return ;
}
if (x <= mid) update(lc, l, mid, x, y, dt);
if (y > mid) update(rc, mid + 1, r, x, y, dt);
}
void travel(int t, int l, int r, int dep)
{
rep(i, SZ(vct[t])) base[dep].insert(vct[t][i]);
if (l == r) {
Ans[l] = base[dep].getans();
return ;
}
base[dep + 1] = base[dep], travel(lc, l, mid, dep + 1),
base[dep + 1] = base[dep], travel(rc, mid + 1, r, dep + 1);
}
int main()
{
#ifdef hany01
File("bzoj4184");
#endif
n = read();
For(i, 1, n) {
register int ai = read();
if (ai > 0) pos[ai] = mp(i, n);
else pos[-ai].y = i - 1;
}
for (map<int, PII>::iterator it = pos.begin(); it != pos.end(); ++ it) {
update(1, 1, n, (*it).y.x, (*it).y.y, (*it).x);
}
travel(1, 1, n, 1);
For(i, 1, n) printf("%d\n", Ans[i]);
return 0;
}
//子曰:“君子周而不比,小人比而不周。”
//--论语,为政篇