扑克牌的面向对象建模

扑克牌的面向对象建模问题：
1.创建两个枚举类型：suit(花色)，Rank(等级)
2.创建两个类：Card(牌)，CardsSet(五张牌的集合)
3.要求CardsSet实现Comparable接口，按照德州扑克规则比较不同牌型的大小

public class Card {
    public String number;
    public String color;

    public Card(String color,String number) {
        super();
        this.number = number;
        this.color = color;
    }

    public String getNumber() {
        return number;
    }

    public String getColor() {
        return color;
    }   
}

 public List<Card> createCardsList(){
        String[] color={"黑桃","红桃","梅花","方块"};
        String[] numbers={"2","3","4","5","6","7","8","9","10","J","Q","K","A"};
        for(String temp:color){
            for(int i=0;i<numbers.length;i++){
                Card card=new Card(temp,numbers[i]);
                cardsList.add(card);
            }
        }
        mixCardsList();
        return cardsList;
    } 

public class Compara implements Comparator<Card>{

    @Override
    public int compare(Card arg0, Card arg1) {
        String color="黑桃  红桃 梅花 方块";
        String numbers="2 3 4 5 6 7 8 9 10 J Q K A";

        int result=numbers.indexOf(arg0.number)-numbers.indexOf(arg1.number);

        if(result<0){
            return -1;
        }else if(result>0){
            return 1;
        }else {
            int result2=color.indexOf(arg0.color)-color.indexOf(arg0.color);
            if(result2>0){
                return 1;
            }else if(result<0){
                return -1;
            }else{
                return 0;
            }
        } 
    }
}

参考文章：https://blog.youkuaiyun.com/Bazingaea/article/details/50886513