Find all possible combinations of k numbers that add up to a number n , given that only numbers from 1 to 9 can be used and each combination should be a unique set of numbers.
Ensure that numbers within the set are sorted in ascending order.
Example 1:
Input: k = 3, n = 7
Output:
[[1,2,4]]
Example 2:
Input: k = 3, n = 9
Output:
[[1,2,6], [1,3,5], [2,3,4]]
public class Solution { public List<List<Integer>> combinationSum3( int k, int n) { List<List<Integer>> res = new ArrayList<List<Integer>>(); if (k< 1 || n< 1 ) return res; helper(res, k, n, 1 , 0 , new ArrayList<Integer>()); return res; } public void helper(List<List<Integer>> res, int k, int n, int cur_k, int cur_sum,List<Integer> item){ if (k== 0 &&cur_sum==n){ res.add(new ArrayList<Integer>(item)); }else if (cur_sum>n||cur_k<= 0 ) return ; for ( int i=cur_k;i<= 9 ;i++){ item.add(i); helper(res, k-1 , n, i+ 1 , cur_sum+i, item); item.remove(item.size()-1 ); } } }
原文链接http://blog.youkuaiyun.com/crazy__chen/article/details/46581071