数值计算的符号转换和溢出

#include<iostream>
#include<algorithm>
using namespace std;
int main()
{
	unsigned short x=32;
	signed short y=-35;
	unsigned short z=x+y;//y根据singed short会被隐式转换为unsigned short，y会被转换成无符号数
	cout<<z<<endl;//结果为65535+1-y+x。此过程中发生一次溢出
	cout<<(unsigned short)y<<endl;//y转换为unsigned short发生一次溢出
}