leetcode——189——Rotate Array

本文提供了一种使用C++编程语言解决旋转数组问题的方法,具体包括通过三次反转操作来实现数组的右移操作。文章详细介绍了算法的实现过程,并通过示例代码加以说明。

Rotate an array of n elements to the right by k steps.

For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].

Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.


class Solution {
public:
    void rotate(vector<int>& nums, int k) {
        
        
        int n = nums.size();
        k = k%n;
        
        reverse(nums,0,n-k-1);
        reverse(nums,n-k,n-1);
        reverse(nums,0,n-1);
        
    }
private:    
    void  reverse(vector<int>& nums, int start, int end) {  
        int i = start;  
        int j = end;  
        int temp = 0;  
        while (i<j) {  
            temp = nums[i];  
            nums[i] = nums[j];  
            nums[j] = temp;  
            ++i;  
            --j;  
        }  
        return;  
    }  

};


评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值