c++ operator重载的例子

本文展示了C++中如何实现运算符重载,包括加、减、乘、除等基本运算符以及自定义类型之间的运算符重载。通过实例代码详细说明了运算符重载的语法和用法。

c++ operator重载的例子

#include <iostream>
using namespace std;
class A
{
public:
    A(double _data = 0.0):data(_data){}
    A& operator = (const A& rhs)
    {
        data = rhs.data;
        return *this;
    }
      
    friend A operator + (const A& lhs,const A& rhs);
    friend A operator - (const A& lhs,const A& rhs);
    friend A operator * (const A& lhs,const A& rhs);
    friend A operator + (const A& lhs,double rhs);
    friend A operator + (double lhs,const A& rhs);
    friend A operator * (const A& lhs,double rhs);
    friend A operator * (double lhs,const A& rhs);
    friend A operator - (const A& lhs,double rhs);
    friend A operator - (double lhs,const A& rhs);
      
      
    friend ostream& operator << (ostream& fout,A& a);
//  A& operator += (const A& rhs);
//  A& operator -= (const A& rhs);
//  A& operator *= (const A& rhs);  
private:
    double data;
};
  
A operator + (const A& lhs,const A& rhs)
{
    A res(0);
    res.data = lhs.data + rhs.data;
    return res;
}
A operator - (const A& lhs,const A& rhs)
{
    A res(0);
    res.data = lhs.data - rhs.data;
    return res;
}
A operator * (const A& lhs,const A& rhs)
{
    A res(0);
    res.data = lhs.data * rhs.data;
    return res;
}
 A operator + (const A& lhs,double rhs)
 {
    A res(0);
    res.data = lhs.data + rhs;
    return res;
}
  
A operator + (double lhs,const A& rhs)
{
    A res(0);
    res.data = lhs + rhs.data;
    return res;
}
A operator * (const A& lhs,double rhs)
{
    A res(0);
    res.data = lhs.data * rhs;
    return res;
}
A operator * (double lhs,const A& rhs)
{
    A res(0);
    res.data = lhs * rhs.data;
    return res;
}
A operator - (const A& lhs,double rhs)
{
    A res(0);
    res.data = lhs.data - rhs;
    return res; 
}
A operator - (double lhs,const A& rhs)
{
    A res(0);
    res.data = lhs - rhs.data;
    return res; 
}
      
ostream& operator << (ostream& fout,A& a)
{
    fout << a.data ;
    return fout;
}
int main(int argc, char* argv[])
{
    A a(2.3);
    A b(1.2);
    A d(3.4);
    A c;
    c = a + b + d;
    c=a+b;
    c=a+1.0;
    c=a-b;
    c=a-1.0;
    c=a*b;
    c=a*1.0;
    cout << c << endl;
      
    c=1.0+2.0*a*a-3.0*a*b;
    cout << c << endl;
    return 0;
}

 

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