UVA1596 - Bug Hunt

In this problem, we consider a simple programming language that has only declarations of onedimensional integer arrays and assignment statements. The problem is to find a bug in the given program.
The syntax of this language is given in BNF as follows:
〈program〉 ::= 〈declaration〉|〈program〉〈declaration〉|〈program〉〈assignment〉
〈declaration〉 ::= 〈array name〉 [〈number〉]〈new line〉
〈assignment〉 ::= 〈array name〉 [〈expression〉]= 〈expression〉〈newline〉
〈expression〉 ::= 〈number〉|〈array name〉 [〈expression〉]
〈number〉 ::= 〈digit〉|〈digit positive〉〈digit string〉
〈digit string〉 ::= 〈digit〉|〈digit〉〈digit string〉
〈digit positive〉 ::= 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9
〈digit〉 ::= 0 | 〈digit positive〉
〈array name〉 ::= a | b | c | d | e | f | g | h | i | j | k | l | m |
n | o | p | q | r | s | t | u | v | w | x | y | z |
A | B | C | D | E | F | G | H | I | J | K | L | M |
N | O | P | Q | R | S | T | U | V | W | X | Y | Z
where 〈new line〉 denotes a new line character (LF).
Characters used in a program are alphabetical letters, decimal digits, =, [, ] and new line characters.
No other characters appear in a program.
A declaration declares an array and specifies its length. Valid indices of an array of length n are
integers between 0 and n − 1, inclusive. Note that the array names are case sensitive, i.e. array a and
array A are different arrays. The initial value of each element in the declared array is undefined.
For example, array a of length 10 and array b of length 5 are declared respectively as follows.
a[10]
b[5]
An expression evaluates to a non-negative integer. A 〈number〉 is interpreted as a decimal integer.
An 〈array name〉 [〈expression〉] evaluates to the value of the 〈expression〉-th element of the array.
An assignment assigns the value denoted by the right hand side to the array element specified by the
left hand side.
Examples of assignments are as follows.
a[0]=3
a[1]=0
a[2]=a[a[1]]
a[a[0]]=a[1]
A program is executed from the first line, line by line. You can assume that an array is declared
once and only
once before any of its element is assigned or referred to.
Given a program, you are requested to find the following bugs.
• An index of an array is invalid.
• An array element that has not been assigned before is referred to in an assignment as an index
of array or as the value to be assigned.
You can assume that other bugs, such as syntax errors, do not appear. You can also assume that
integers represented by 〈number〉s are between 0 and 231 − 1 (= 2147483647), inclusive.
Input
The input consists of multiple datasets followed by a line which contains only a single ‘.’ (period).
Each dataset consists of a program also followed by a line which contains only a single ‘.’ (period).
A program does not exceed 1000 lines. Any line does not exceed 80 characters excluding a new line
character.
Output
For each program in the input, you should answer the line number of the assignment in which the first
bug appears. The line numbers start with 1 for each program. If the program does not have a bug,
you should answer zero. The output should not contain extra characters such as spaces.
Sample Input
a[3]
a[0]=a[1]
.
x[1]
x[0]=x[0]
.
a[0]
a[0]=1
.
b[2]
b[0]=2
b[1]=b[b[0]]
b[0]=b[1]
.
g[2]
G[10]
g[0]=0
g[1]=G[0]
.
a[2147483647]
a[0]=1
B[2]
B[a[0]]=2
a[B[a[0]]]=3
a[2147483646]=a[2]
.
.
Sample Output
2
2
2
3
4
0

#include<bits/stdc++.h>
using namespace std;

struct Array{
    int siz;
    map<int,int>values;
    void init(int sz){
        siz=sz;
        values.clear();
    }

    Array(){remov();}

    void remov(){siz=-1;values.clear();}

    bool exists(){return siz>=0;}

    bool getValue(int idx,int &v){
        if(values.count(idx)){
            v=values[idx];
            return true;
        }
        return false;
    }

    bool setValue(int idx,int v){
        if(idx>=siz) return false;
        values[idx]=v;  
        return true;
    }
}arrays[128];

bool eval(const char* s,int &v){
    if(isdigit(s[0])){
        sscanf(s,"%d",&v);return true;
    }
    char a=s[0];
    Array& ary=arrays[a];
    if(!ary.exists()) return false;
    int idx;
    if(!eval(s+2,idx)) return false;
    return ary.getValue(idx,v);
}

int main(){
    //freopen("datain.txt","r",stdin);
    char line[128];
    int lineNum=0,bugLine=0;
    while(scanf("%s",line)==1){
        int expLen=strlen(line);
        if(line[0]=='.'){
            if(lineNum)printf("%d\n",bugLine);
            for(int i=0;i<128;i++) arrays[i].remov();
            lineNum=0;
            bugLine=0;
            continue;
        }
        if(bugLine>0)continue;
        const char * pEq=strchr(line,'=');
        if(pEq){
            Array& ary=arrays[line[0]];
            int rv,index,lLen=pEq-line;
            if(ary.exists()&&eval(pEq+1,rv)&&eval(line+2,index)&&ary.setValue(index,rv))
                lineNum++;
            else bugLine=lineNum+1;
        } else{
            char name;int sz;
            sscanf(line,"%c[%d]",&name,&sz);
            arrays[name].init(sz);
            lineNum++;
        }
    }
}

 

### GIB-UVA ERP-BCI HDF5 文件格式及其处理方法 HDF5 是一种用于存储大量科学数据的文件格式,广泛应用于神经科学研究领域。对于 GIB-UVA ERP-BCI 数据集中的 HDF5 文件,通常包含了脑电图(EEG)信号以及其他元数据信息。以下是关于该类文件的一些重要细节以及如何对其进行处理的方法。 #### 1. HDF5 文件结构概述 HDF5 文件是一种分层的数据存储格式,类似于文件系统的目录树结构。它支持多种数据类型,包括数组、表格和字符串等。在 GIB-UVA ERP-BCI 的上下文中,这些文件可能包含以下内容: - **实验记录**:如时间戳、采样率和其他实验参数。 - **原始 EEG 数据**:多通道的时间序列数据。 - **事件标记**:表示刺激呈现或其他行为事件的时间点。 这种层次化的结构使得研究人员可以轻松访问特定部分的数据而无需加载整个文件[^3]。 #### 2. 处理 HDF5 文件所需的工具 为了读取和操作 HDF5 文件,可以使用 Python 中的 `h5py` 或 MATLAB 提供的相关库。下面是一个简单的例子展示如何利用 `h5py` 打开并探索一个 HDF5 文件的内容: ```python import h5py def explore_hdf5(file_path): with h5py.File(file_path, 'r') as f: print("Keys:", list(f.keys())) # 列出顶层组名 for key in f.keys(): item = f[key] if isinstance(item, h5py.Dataset): print(f"{key} is a dataset with shape {item.shape}") elif isinstance(item, h5py.Group): print(f"{key} is a group containing:") for sub_key in item.keys(): print(f" - {sub_key}") explore_hdf5('example.h5') ``` 上述脚本会打印出给定 HDF5 文件的所有顶级键,并区分它们是数据集还是子组[^4]。 #### 3. 内存管理注意事项 如果尝试运行某些大型模型(例如 DeepSeek-R1),可能会遇到内存不足的情况,正如引用中提到的例子所示[^2]。在这种情况下,建议采取以下措施来优化资源分配: - 使用更高效的算法减少计算需求; - 增加物理 RAM 或启用虚拟内存扩展; - 对于 GPU 加速环境,考虑调整批次大小或切换到较低精度浮点数运算模式(FP16 vs FP32)。 此外,在处理大尺寸的 HDF5 文件时也需要注意类似的性能瓶颈问题——可以通过逐块加载而非一次性全部载入的方式来缓解这一挑战[^5]。 #### 4. 特殊情况下的预处理技术 针对 BCI 应用场景下采集得到的高维时空域特征矩阵,往往还需要执行一系列标准化流程,比如去噪滤波器应用、基线校正以及重参考变换等等。具体实现取决于实际研究目标和个人偏好设置等因素影响。 --- ###
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