1001 A+B Format (甲级)

小蒋大魔王

于 2020-10-29 11:07:39 发布

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分类专栏： pat_trainning解析文章标签： c++ 算法

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本文介绍了一个简单的C++程序，该程序接收两个整数作为输入，并以标准格式输出它们的和，其中数字每三位用逗号分隔。程序考虑了正负数的情况并正确处理了绝对值求和。

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题目

Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there> are less than four digits).

Input Specification: Each input file contains one test case. Each case
contains a pair of integers a and b where −10 6 ≤a,b≤10 6 .
The numbers are separated by a space.

Output Specification: For each test case, you should output the sum of
a and b in one line. The sum must be written in the standard format.

Sample Input:
-1000000 9 Sample Output:
-999,991

代码

#include<bits/stdc++.h>
using namespace std;

int main()
{
	int a,b;
	scanf("%d%d",&a,&b);
	int sum=a+b;
	if(sum==0) printf("0");
	int num=0;
	int c[10];
	int temp=abs(sum);
	while(temp){
		c[num]=temp%10;
		temp/=10;
		num++;
	}

	if(sum<0){
		printf("-");
	}
	for(int i=num-1;i>=0;i--){
		printf("%d",c[i]);
		if(i%3==0&&i!=0) printf(",");
	}
	printf("\n");

	return 0;
}