题目
给定一个矩阵matrix,把矩阵顺时针转动90度:
1 2 3
4 5 6
7 8 9
->
7 4 1
8 5 2
9 6 3
思路
比较简单的思路
1)先上下对称
->
7 8 9
4 5 6
1 2 3
2)对角互换
->
7 4 1
8 5 2
9 6 3
实现
def rotate(matrix):
if matrix is None or len(matrix) == 0 or len(matrix[0]) != len(matrix):
return
size = len(matrix)
for i in range(size//2):
matrix[i], matrix[size-i-1] = matrix[size-i-1], matrix[i]
for i in range(size):
for j in range(i):
matrix[i][j], matrix[j][i] = matrix[j][i], matrix[i][j]
return matrix
测试
def test_rotate(size):
n = 1
mat = []
for i in range(size):
row = [n+j for j in range(size)]
n += size
mat.append(row)
print(mat)
rotate(mat)
print(mat)
if __name__ == '__main__':
test_rotate(3)
结果
[[1, 2, 3], [4, 5, 6], [7, 8, 9]]
[[7, 4, 1], [8, 5, 2], [9, 6, 3]]