#include <stdio.h> int main() {
//有局限性 /*自己的方法 int time,min; scanf("%d %d",&time,&min); int zong , zongtime,zongmin; zong = time/100*60+time%100+min; zongtime=zong / 60; zongmin=zong%60; printf ("%d%d",zongtime,zongmin); return 0; */ //通过的审核的. int time,minute; scanf("%d %d",&time, &minute); int m, t, m1; //m为总分钟数,t为最后的小时数,m1为最后的分钟数 m = (time / 100 * 60 + time % 100 + minute); t = m / 60; m1 = m - t * 60; time = t * 100 + m1; printf("%d", time); return 0; }
然后是几点
最新推荐文章于 2024-04-09 22:09:45 发布