1. 题目描述
力扣226.翻转二叉树
给你一棵二叉树的根节点 root ,翻转这棵二叉树,并返回其根节点。
示例 1:
输入:root = [4,2,7,1,3,6,9]
输出:[4,7,2,9,6,3,1]
实例2:
输入:root = [2,1,3]
输出:[2,3,1]
示例3:
输入:root = [ ]
输出:[ ]
2. 思路
对于每一个非空节点,反转他的左右子节点,然后递归翻转该结点的子节点的子节点
3. 代码实现
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* struct TreeNode *left;
* struct TreeNode *right;
* };
*/
struct TreeNode* invertTree(struct TreeNode* root) {
if(root)
{
struct TreeNode* ptr = root->left;
root->left = root->right;
root->right = ptr;
invertTree(root->left);
invertTree(root->right);
}
return root;
}