给一个开始时间和一个结束时间，求中间的连续时间（用java实现）？

给一个开始时间和一个结束时间，求中间的连续时间（用java实现）？如：开始时间为140825，结束时间为140902，那连续时间为 140825，140826，140827，140828，140829，140830，140831，140901，140902

 

import java.text.ParseException;
import java.text.SimpleDateFormat;
import java.util.ArrayList;
import java.util.Calendar;
import java.util.Date;
import java.util.GregorianCalendar;
import java.util.List;

/**
 *时间格式化工具类
 */
public class ChartDateFormatUtils {
	/**
	 * 获取两个时间相差的天数
	 * 
	 * @param date1
	 * @param date2
	 * @return
	 */
	public static int getBetweenDays(Date date1, Date date2) {
		Calendar cal = Calendar.getInstance();
		cal.setTime(date1);
		long time1 = cal.getTimeInMillis();
		cal.setTime(date2);
		long time2 = cal.getTimeInMillis();
		long between_days = (time2 - time1) / (1000 * 3600 * 24);

		return Integer.parseInt(String.valueOf(between_days));
	}

	/**
	 * 获取连续时间
	 * 
	 * @param tempList
	 * @return
	 * @throws ParseException
	 */
	@SuppressWarnings("deprecation")
	public static List<String> getContinuousTime(List<String> tempList) throws ParseException {

		String startTime = tempList.get(0);
		String endTime = tempList.get(tempList.size() - 1);

		SimpleDateFormat sdf = new SimpleDateFormat("yyMMdd");
		Date startDate = sdf.parse(startTime);
		Date endDate = sdf.parse(endTime);

		int betweenDay = getBetweenDays(startDate, endDate) + 1;

		Calendar curTime = new GregorianCalendar(startDate.getYear(), startDate.getMonth(), startDate.getDate());

		SimpleDateFormat dateformat2 = new SimpleDateFormat("yyMMdd");
		List<String> dataList = new ArrayList<String>();

		for (int i = 1; i <= betweenDay; i++) {
			String dateKey = dateformat2.format(curTime.getTime());
			dataList.add(dateKey);
			curTime.add(Calendar.DATE, 1);
		}

		return dataList;

	}

	public static void main(String[] args) {
		List<String> tempList = new ArrayList<String>();
		tempList.add("140715");
		tempList.add("140717");
		tempList.add("140817");

		try {
			for (String str : getContinuousTime(tempList)) {
				System.out.println(str);
			}
		} catch (ParseException e) {
			e.printStackTrace();
		}

	}

}