LeetCode77.组合
class Solution {
public:
vector<vector<int>> result;
vector<int> path;
vector<vector<int>> combine(int n, int k) {
dfs(n, k, 1);
return result;
}
void dfs(int n, int k, int startIndex){
if(path.size() == k){
result.push_back(path);
return;
}
for(int i = startIndex; i <= n; i++){
path.push_back(i);
dfs(n, k, i + 1);
path.pop_back();
}
}
};
LeetCode216.组合总和Ⅲ
class Solution {
public:
vector<vector<int>> result;
vector<int> combine;
int sum = 0;
vector<vector<int>> combinationSum3(int k, int n) {
dfs(k, n, 1, sum);
return result;
}
void dfs(int k, int n, int startIndex, int sum){
if(combine.size() == k){
if(sum == n){
result.push_back(combine);
}
return;
}
for(int i = startIndex; i <= 9 - (k - combine.size()) + 1; i++){
combine.push_back(i);
sum += i;
dfs(k, n, i + 1, sum);
sum -= i;
combine.pop_back();
}
}
};
LeetCode17.电话号码的字母组合
class Solution {
public:
std::map<char,std::vector<char>> numToLetter = {{'2',{'a','b','c'}},{'3',{'d','e','f'}},{'4',{'g','h','i'}},{'5',{'j','k','l'}},
{'6',{'m','n','o'}},{'7',{'p','q','r','s'}},{'8',{'t','u','v'}},{'9',{'w','x','y','z'}}};
std::string combine = "";
vector<string> result;
vector<string> letterCombinations(string digits) {
if(digits == ""){
return result;
}
dfs(digits,0);
return result;
}
void dfs(string digits, int index){
if(combine.length() == digits.length()){
result.push_back(combine);
return;
}
char cur = digits[index];
for(int i = 0; i < numToLetter[cur].size(); i++){
combine.push_back(numToLetter[cur][i]);
dfs(digits,index + 1);
combine.pop_back();
}
}
};