LeetCode——7. Reverse Integer

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本文深入解析了LeetCode上编号为7的题目“反转整数”。介绍了如何在32位有符号整数范围内反转数字，并提供了Python实现代码。特别注意处理反转后可能超出整数范围的异常情况。

LeetCode——7. Reverse Integer

Description
Example
Note
Solution

Description

Given a 32-bit signed integer, reverse digits of an integer.。

Example

Example 1:

Input: 123
Output: 321

Example 2:

Input: -123
Output: -321

Example 3:

Input: 120
Output: 21

Note

Assume we are dealing with an environment which could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.

Solution

class Solution(object):
    def reverse(self, x):
        """
        :type x: int
        :rtype: int
        """
        
        result = 0
        
        symbol = 1
        
        if x <0:
            symbol = -1 #设置表示负数时的情况。
            x = -x
        
        while x != 0:
            
            result = result * 10 + x % 10
            
            x /= 10
            
        return 0 if result > pow(2,31) else result * symbol #判断重新生成的数是否超出了数的界限