#include <vector>
#include <iostream>
using namespace std;
/*
Given a 2D matrix, find the sum of the elements inside the rectangle defined
by its upper left corner(row1, col1) and lower right corner(row2, col2).
For exmaple:
Given matrix = [
[3, 0, 1, 4, 2],
[5, 6, 3, 2, 1],
[1, 2, 0, 1, 5],
[4, 1, 0, 1, 7],
[1, 0, 3, 0, 5]]
sumRegion(2, 1, 4, 3) -> 8
update(3, 2, 2)
sumRegion(2, 1, 4, 3) -> 10
Note:
The matrix is only modifiable by the update function
You may assume the number of calls to update and sumRegion function is distributed evenly.
You may assume that row1 <= row2 and col1 <= col2.
*/
class NumMatrix {
private:
vector< vector<int> > newMatrix;
public:
NumMatrix(vector< vector<int> >& matrix) {
for(int i = 0; i < matrix.size(); ++i) {
newMatrix.push_back(vector<int>(matrix[0].size() + 1, 0));
}
for(int i = 0; i < matrix.size(); ++i) {
for(int j = 0; j < matrix[i].size(); ++j) {
newMatrix[i][j+1] = newMatrix[i][j] + matrix[i][j];
}
}
}
void update(int row, int col, int val) {
int diff = val - (newMatrix[row][col + 1] - newMatrix[row][col]);
for(int i = col + 1; i < newMatrix[row].size(); ++i) {
newMatrix[row][i] += diff;
}
}
int sumRegion(int row1, int col1, int row2, int col2) {
int sum = 0;
for(int i = row1; i <= row2; ++i) {
sum += newMatrix[i][col2 + 1] - newMatrix[i][col1];
}
return sum;
}
};
int main(void) {
vector< vector<int> > matrix_test{
{3, 0, 1, 4, 2},
{5, 6, 3, 2, 1},
{1, 2, 0, 1, 5},
{4, 1, 0, 1, 7},
{1, 0, 3, 0, 5}};
NumMatrix matrix(matrix_test);
cout << matrix.sumRegion(2, 1, 4, 3) << endl;
matrix.update(3, 2, 2);
cout << matrix.sumRegion(2, 1, 4, 3) << endl;
}
LeetCode 308. Range Sum Query 2D - Mutable
最新推荐文章于 2025-05-18 02:30:00 发布
本文介绍了一个名为NumMatrix的类实现,该类能够高效地处理二维矩阵中指定矩形区域内的元素求和操作,并支持对矩阵元素的更新。通过预处理方式,实现了sumRegion与update方法,以优化重复调用时的效率。
部署运行你感兴趣的模型镜像
您可能感兴趣的与本文相关的镜像
ACE-Step
音乐合成
ACE-Step
ACE-Step是由中国团队阶跃星辰(StepFun)与ACE Studio联手打造的开源音乐生成模型。 它拥有3.5B参数量,支持快速高质量生成、强可控性和易于拓展的特点。 最厉害的是,它可以生成多种语言的歌曲,包括但不限于中文、英文、日文等19种语言

319

被折叠的 条评论
为什么被折叠?



