17 ms, 完全的merge方法, 就是将一个数组,不停的分成两个数组,进行合并,基本类似于归并排序
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
public class Solution {
public ListNode mergeKLists(ListNode[] lists) {
if(lists.length == 0){
return null;
}
if (lists.length == 1){
return lists[0];
}else if (lists.length == 2){
return mergetwoList(lists[0],lists[1]);
}else {
return mergetwoList(mergeKLists(Arrays.copyOfRange(lists,0,lists.length/2)),
mergeKLists(Arrays.copyOfRange(lists,lists.length/2,lists.length)));
}
}
private ListNode mergetwoList(ListNode p1,ListNode p2){
ListNode head = new ListNode(0);
ListNode p = head;
while (p1!=null&&p2!=null){
if (p1.val<p2.val){
p.next = p1;
p1 = p1.next;
}else {
p.next = p2;
p2 = p2.next;
}
p = p.next;
}
if (p1!=null){
p.next = p1;
}
if (p2!=null){
p.next = p2;
}
return head.next;
}
}