js如何避免同一元素绑定多次点击事件

解决办法，判断元素有没有点击事件，没有就绑定

if (element.hasAttribute('onclick')) {
      console.log('元素有onclick事件');
} else {
      console.log('元素没有onclick事件');
      element.addEventListener('click', finishEvent); 
}

doc.querySelectorAll('.test-item-finish').forEach(function(element) {
                let finishEvent = function(event) {
                  let userId = sessionStorage.getItem("userId");
                  if (userId == null || userId == "" || userId == "null") {
                    if (config.configData.loginType == "wx") {
                      that.showScanLogin = true;
                    } else {
                      that.$router.push({
                          path: '/login',
                      }) 
                    }   
                    return false;                 
                  } 
                  let postBody = {dataId: element.dataset.id};
                  that.$showLoading();
                  testItemFinish(postBody).then((res) => {
                    that.$closeLoading();
                    that.queryClick();
                  })  
            } 
            if (element.hasAttribute('onclick')) {
              console.log('元素有onclick事件');
            } else {
              console.log('元素没有onclick事件');
              element.addEventListener('click', finishEvent); 
            }
 });