Hibernate 多对多单向关联

映射方法

<hibernate-mapping>

<class name="com.lavasoft.dx._n_n.Personnn" table="PERSON_nn">

<id name="personid">

<generator class="identity"/>

</id>

<property name="name"/>

<property name="age"/>

<!-- 映射集合属性，join_1ntab 是 连接表表名-->

<set name="addresses"

table="join_nn"

>

<!-- “column="personid" ” 确定PERSON_1ntab 表关联到连接表的外键列名-->

<key column="personid"/>

<!-- “column="addressid" ” 关联PERSON_1ntab 表的Address1ntab 对 象的id 在连接表中的列名-->

<many-to-many

column="addressid"

class="com.lavasoft.dx._n_n.Addressnn"/>

</set>

</class>

</hibernate-mapping>

<hibernate-mapping>

<class name="com.lavasoft.dx._n_n.Addressnn" table="ADDRESS_nn">

<id name="addressid">

<generator class="identity"/>

</id>

<property name="addressdetail"/>

</class>

</hibernate-mapping>

测试方法

public class Test_nn {

public static void main(String[] args){

Addressnn add1=new Addressnn();

Addressnn add2=new Addressnn();

Addressnn add3=new Addressnn();

Personnn p1=new Personnn();

Personnn p2=new Personnn();

add1.setAddressdetail(" 郑州市经三路");

add2.setAddressdetail(" 合肥市宿州路");

add3.setAddressdetail(" 北京市长安路");

p1.setName("wang");

p1.setAge(30);

p2.setName("lee");

p2.setAge(50);

p1.getAddresses().add(add1);

p1.getAddresses().add(add2);

p2.getAddresses().add(add2);

p2.getAddresses().add(add3);

Session session= HibernateUtil.getCurrentSession();

Transaction tx=session.beginTransaction();

session.save(add1);

session.save(add2);

session.save(add3);

session.save(p1);

session.save(p2);

tx.commit();

HibernateUtil.closeSession();

}

}