set集合下的函数:
difference()可以求差集
>>> set(a).difference(set(b))
set([4, 5, 6, 7, 8, 9])
>>> a
[1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> b
[1, 2, 3]
>>> set(a).difference(set(b))
set([4, 5, 6, 7, 8, 9])
union()可以求并集
>>> set(a).union(set(b))
set([1, 2, 3, 4, 5, 6, 7, 8, 9])
intersection()可以求交集
>>> set(a).intersection(set(b))
set([1, 2, 3])