Stack 简介
Stack 是一种后进先出的数据结构实现,也就是LIFO(last in first out). 举个例子吧,大学食堂的大妈会摊煎饼。摊好了就放到桌子上,后面摊好的会叠加到之前一个上。如果有个人来买,大妈通常会把最上面的煎饼给到到你。当然,一般情况她不会从最底下抽一个出来给你。那样容易把饼子扯烂了,而且从底下拿饼子,就是大妈在演示FIFO(first in firt out)啦。开个玩笑,一般是大家在旁边等着大妈摊饼子。煎饼果子切克闹,有钱没钱来一套。走起。
Stack class
Stack 很单纯,只有一个父类 Vector,它通过五个操作扩展了Vector类,这些操作允许将 Vector 视为 Stack。提供了通常的 推入 push() 和 弹出 pop() 操作,以及一种 查看堆栈顶部项目的方法peek()
public class Stack<E> extends Vector<E> {}
当stack倍创建后,他是不包含任何对象的。Deque接口及其实现提供了一组更完整和一致的LIFO堆栈操作,应优先于此类使用。
Deque stack = new ArrayDeque();
代码不多,就全部贴上来:
public
class Stack<E> extends Vector<E> {
/**
* Creates an empty Stack.
*/
public Stack() {
}
/**
* Pushes an item onto the top of this stack. This has exactly
* the same effect as:
* <blockquote><pre>
* addElement(item)</pre></blockquote>
*
* @param item the item to be pushed onto this stack.
* @return the <code>item</code> argument.
* @see java.util.Vector#addElement
*/
public E push(E item) {
addElement(item);
return item;
}
/**
* Removes the object at the top of this stack and returns that
* object as the value of this function.
*
* @return The object at the top of this stack (the last item
* of the <tt>Vector</tt> object).
* @throws EmptyStackException if this stack is empty.
*/
public synchronized E pop() {
E obj;
int len = size();
obj = peek();
removeElementAt(len - 1);
return obj;
}
/**
* Looks at the object at the top of this stack without removing it
* from the stack.
*
* @return the object at the top of this stack (the last item
* of the <tt>Vector</tt> object).
* @throws EmptyStackException if this stack is empty.
*/
public synchronized E peek() {
int len = size();
if (len == 0)
throw new EmptyStackException();
return elementAt(len - 1);
}
/**
* Tests if this stack is empty.
*
* @return <code>true</code> if and only if this stack contains
* no items; <code>false</code> otherwise.
*/
public boolean empty() {
return size() == 0;
}
/**
* Returns the 1-based position where an object is on this stack.
* If the object <tt>o</tt> occurs as an item in this stack, this
* method returns the distance from the top of the stack of the
* occurrence nearest the top of the stack; the topmost item on the
* stack is considered to be at distance <tt>1</tt>. The <tt>equals</tt>
* method is used to compare <tt>o</tt> to the
* items in this stack.
*
* @param o the desired object.
* @return the 1-based position from the top of the stack where
* the object is located; the return value <code>-1</code>
* indicates that the object is not on the stack.
*/
public synchronized int search(Object o) {
int i = lastIndexOf(o);
if (i >= 0) {
return size() - i;
}
return -1;
}
/** use serialVersionUID from JDK 1.0.2 for interoperability */
private static final long serialVersionUID = 1224463164541339165L;
}
可以看到,Stack 也是做了同步操作的。