UVa 1585 Score

本题是较为简单的字符串匹配问题，在匹配过程中遇到’O’则累加，遇到’X’则重置0，以下是代码部分

    #include <algorithm>  
    #include <iostream>  
    #include <cstdlib>  
    #include <cstdio>  

    using namespace std;  

    char str[81];  //输入的目标匹配串
    int  score[81];  //累加计数变量

    int main()  
    {  
        int n;  
        scanf("%d",&n);  
        while (n --) {  
            scanf("%s",str);  
            score[0] = (str[0] == 'O');  
            for (int i = 1 ; str[i] ; ++ i) {  //str[i]=='\0'时退出循环
                score[i] = score[i-1]+1;  //变量累加
                if (str[i] == 'X')  
                    score[i] = 0;  
            }  
            int sum = 0;  
            for (int i = 0 ; str[i] ; ++ i)  
                sum += score[i];  

            printf("%d\n",sum);   
        }  
        return 0;  
    }