uva 1585 Score

本文介绍了一个简单的算法,用于计算一种特殊格式的客观测试答案的得分。对于由'O'和'X'组成的字符串,每个'O'的分数等于其连续'O'的数量。文章提供了完整的C++实现代码,并解释了输入输出格式及样例。

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原题:
There is an objective test result such as “OOXXOXXOOO”. An ‘O’ means a correct answer of a problem and an ‘X’ means a wrong answer. The score of each problem of this test is calculated by itself and its just previous consecutive ‘O’s only when the answer is correct. For example, the score of the 10th problem is 3 that is obtained by itself and its two previous consecutive ‘O’s. Therefore, the score of “OOXXOXXOOO” is 10 which is calculated by “1+2+0+0+1+0+0+1+2+3”.
You are to write a program calculating the scores of test results.
Input
Your program is to read from standard input. The input consists of T test cases. The number of test cases T is given in the first line of the input. Each test case starts with a line containing a string composed by ‘O’ and ‘X’ and the length of the string is more than 0 and less than 80. There is no spaces
between ‘O’ and ‘X’.
Output
Your program is to write to standard output. Print exactly one line for each test case. The line is to contain the score of the test case.
Sample Input
5
OOXXOXXOOO
OOXXOOXXOO
OXOXOXOXOXOXOX
OOOOOOOOOO
OOOOXOOOOXOOOOX
Sample Output
10
9
7
55
30

中文:
给你一个字符串,X的得分为0,O的得分为连续的O的个数,问你这个字符串的总分是多少?

#include <bits/stdc++.h>
using namespace std;
int main()
{
    ios::sync_with_stdio(false);
    int n;
    cin>>n;
    string s;
    while(n--)
    {
        cin>>s;
        int ans=0;
        int ind=0;
        for(int i=0;i<s.size();i++)
        {
            if(s[i]=='X')
                ind=0;
            else
            {
                ind++;
                ans+=ind;
            }
        }
        cout<<ans<<endl;
    }
    return 0;
}

解答:
超级简单题,作为入门题都算是简单的。

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