这题好水,求垂直的线段,求出原来线段的长度,在原点旋转90即可。
#include<iostream>
#include<algorithm>
#include<cstdio>
using namespace std;
struct Point{
int x,y;
};
int main(){
int s,n,tt=1;
Point a1,b1,a2,b2;
scanf("%d",&n);
while(n--){
scanf("%d%d%d%d",&a1.x,&a1.y,&a2.x,&a2.y);
if(a1.x >a2.x) swap(a1,a2);
int dy = abs(a1.y-a2.y),dx = abs(a1.x-a2.x);
b1.x = 0, b2.x = dy;
if(a1.y < a2.y)
b1.y = dx,b2.y=0;
else b1.y = 0,b2.y=dx;
printf("Case %d: %d %d %d %d\n",tt++,b1.x,b1.y,b2.x,b2.y);
}
return 0;
}