POJ 1083 Moving Tables

The famous ACM (Advanced Computer Maker) Company has rented a floor of a building whose shape is in the following figure.

The floor has 200 rooms each on the north side and south side along the corridor. Recently the Company made a plan to reform its system. The reform includes moving a lot of tables between rooms. Because the corridor is narrow and all the tables are big, only one table can pass through the corridor. Some plan is needed to make the moving efficient. The manager figured out the following plan: Moving a table from a room to another room can be done within 10 minutes. When moving a table from room i to room j, the part of the corridor between the front of room i and the front of room j is used. So, during each 10 minutes, several moving between two rooms not sharing the same part of the corridor will be done simultaneously. To make it clear the manager illustrated the possible cases and impossible cases of simultaneous moving.

For each room, at most one table will be either moved in or moved out. Now, the manager seeks out a method to minimize the time to move all the tables. Your job is to write a program to solve the manager’s problem.

Input

The input consists of T test cases. The number of test cases ) (T is given in the first line of the input file. Each test case begins with a line containing an integer N , 1 <= N <= 200, that represents the number of tables to move.
Each of the following N lines contains two positive integers s and t, representing that a table is to move from room number s to room number t each room number appears at most once in the N lines). From the 3 + N -rd
line, the remaining test cases are listed in the same manner as above.

Output

The output should contain the minimum time in minutes to complete the moving, one per line.

Sample Input

3 
4 
10 20 
30 40 
50 60 
70 80 
2 
1 3 
2 200 
3 
10 100 
20 80 
30 50 

Sample Output

10
20
30

题意描述：

给出n对房间号，然后让你从第一个房间里边移动一张桌子，移到第二个房间里边，无论多远10分钟之内都可以完成，但是走廊每次只能移动一张，问n对全不完成，需要多长时间。

解题思路：

由题的图一可以看出来，它是单号一边双号一边，因此需要判断初始和结束房间的单双号，（假设从2号移到5号，因为2号在移动的时候1号也被占用，同理移到5号时6号也被占用了。）用一个数组标记之后找出最大的层数10就可以了。

AC代码：

#include<stdio.h>
#include<string.h>
int main(void)
{
	int t,n,count,s,t1,book[410],max,z,temp;
	scanf("%d",&t);
	while(t--){
		count=1;
		z=-1;max=-1;
		memset(book,0,sizeof(book));
		scanf("%d",&n);
		for(int i=0;i<n;i++){
			scanf("%d%d",&s,&t1);
			if(s>t1){
				temp=s;
				s=t1;
				t1=temp;
			}
			if(s%2==0)
				s--;
			if(t1%2!=0)
				t1++;
			for(int j=s;j<=t1;j++)
				book[j]++;
		}
		for(int k=1;k<=400;k++)
			if(max<book[k])
				max=book[k];
		printf("%d\n",max*10);	
	}
	return 0;
}