566. Reshape the Matrix

本文介绍了一个基于MATLAB中'reshape'函数原理的矩阵重塑算法。该算法接收一个二维数组及目标行数和列数作为输入参数,尝试将原矩阵重塑为目标尺寸,同时保持元素的行遍历顺序不变。若重塑成功,则输出新矩阵;否则返回原矩阵。

In MATLAB, there is a very useful function called 'reshape', which can reshape a matrix into a new one with different size but keep its original data.

You're given a matrix represented by a two-dimensional array, and two positive integers r and c representing the row number and column number of the wanted reshaped matrix, respectively.

The reshaped matrix need to be filled with all the elements of the original matrix in the same row-traversingorder as they were.

If the 'reshape' operation with given parameters is possible and legal, output the new reshaped matrix; Otherwise, output the original matrix.

Example 1:

Input: 
nums = 
[[1,2],
 [3,4]]
r = 1, c = 4
Output: 
[[1,2,3,4]]
Explanation:
The row-traversing of nums is [1,2,3,4]. The new reshaped matrix is a 1 * 4 matrix, fill it row by row by using the previous list.

Example 2:

Input: 
nums = 
[[1,2],
 [3,4]]
r = 2, c = 4
Output: 
[[1,2],
 [3,4]]
Explanation:
There is no way to reshape a 2 * 2 matrix to a 2 * 4 matrix. So output the original matrix.

Note:

  1. The height and width of the given matrix is in range [1, 100].
  2. The given r and c are all positive.

程序如下所示:

class Solution {
    public int[][] matrixReshape(int[][] nums, int r, int c) {
        int row = nums.length;
        if (row == 0){
            return nums;
        }
        int col = nums[0].length;
        if (row*col != r*c){
            return nums;
        }
        int[][] res = new int[r][c];
        int index = 0;
        for (int i = 0; i < row; ++ i){
            for (int j = 0; j < col; ++ j){
                res[index/c][index%c] = nums[i][j];
                index ++;
            }
        }
        return res;
    }
}

 

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