Given a string s, find the longest palindromic subsequence's length in s. You may assume that the maximum length of s is 1000.
Example 1:
Input:
"bbbab"
Output:
4
One possible longest palindromic subsequence is "bbbb".
Example 2:
Input:
"cbbd"
Output:
2
One possible longest palindromic subsequence is "bb".
DP求解,程序如下所示:
class Solution {
public int longestPalindromeSubseq(String s) {
int len = s.length();
int[][] dp = new int[len][len];
for (int i = len - 1; i >= 0; -- i){
dp[i][i] = 1;
for (int j = i + 1; j < len; ++ j){
if (s.charAt(i) == s.charAt(j)){
dp[i][j] = dp[i+1][j-1] + 2;
}
else {
dp[i][j] = Math.max(dp[i][j-1], dp[i+1][j]);
}
}
}
return dp[0][len-1];
}
}