HOJ 2076 Series Determination

http://acm.hit.edu.cn/hoj/problem/view?id=2076

二元一次方程组

给出f(0), f(1), f(2) 求 f(3), f(4), f(5)

#include <stdio.h>

int main()
{
    double f[8], a, b, c;

    while (scanf("%lf %lf %lf",&f[0],&f[1],&f[2])!=EOF)
    {
        c = f[0];
        a = ( (f[2] + f[0]) / 2) - f[1];
        b = f[1] - f[0] - a;
        f[3] = a * 9 + b * 3 + c;
        f[4] = a * 16 + b * 4 + c;
        f[5] = a * 25 + b * 5 + c;
        printf("%.0lf %.0lf %.0lf\n",f[3], f[4], f[5]);
    }

    return 0;
}