http://acm.hit.edu.cn/hoj/problem/view?id=2869
一个人有e+f个空瓶子
c个空瓶子可以换一瓶苏打水
求这个人可以喝几瓶苏打水
喝过的瓶子可以再换
#include <stdio.h>
int main()
{
int e, f, c, remain, sum;
while (scanf("%d %d %d", &e, &f, &c) != EOF)
{
sum = 0;
remain = e + f;
while (remain >= c)
{
sum += remain / c;
remain = remain / c + remain % c;
}
printf("%d\n", sum);
}
return 0;
}
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