python3 zip()

最新推荐文章于 2024-05-10 19:52:06 发布

entehen

最新推荐文章于 2024-05-10 19:52:06 发布

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本文介绍如何创建一个聚合迭代器，从多个迭代器中提取元素并组合成元组，详细解释了zip函数的工作原理及其等价实现，并通过实例展示了如何使用zip函数将迭代器聚合为元组。

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Make an iterator that aggregates elements from each of the iterables.
Returns an iterator of tuples, where the i-th tuple contains the
i-th element from each of the argument sequences or iterables. The
iterator stops when the shortest input iterable is exhausted. With a single
iterable argument, it returns an iterator of 1-tuples. With no arguments, it
returns an empty iterator. Equivalent to:
def zip(*iterables):
    # zip('ABCD', 'xy') --> Ax By
    sentinel = object()
    iterables = [iter(it) for it in iterables]
    while iterables:
        result = []
        for it in iterables:
            elem = next(it, sentinel)
            if elem is sentinel:
                return
            result.append(elem)
        yield tuple(result)
举例：
>>> k = list(zip(*[[1,2,3],[4,5,6]]))
>>> k
[(1, 4), (2, 5), (3, 6)]

zip()是内置函数，能把迭代对象进行聚合，返回值是迭代对象-聚合后的元组，用list()函数把它转化为列表

文档那个等价函数值得学习，那个iter()、next()用法并不简单。

>>> k = list(zip(*[[1,2,3],[4,5,6]]))
>>> k
[(1, 4), (2, 5), (3, 6)]
>>> k=zip(*[[1,2,3],[4,5,6]])
>>> k
<zip object at 0x000000000313F088>
>>> list(k)
[(1, 4), (2, 5), (3, 6)]