Given n points
on a 2D plane, find the maximum number of points that lie on the same straight line.
思路:这个代码存在很多不严谨之处。
</pre><pre name="code" class="java">/**
* Definition for a point.
* class Point {
* int x;
* int y;
* Point() { x = 0; y = 0; }
* Point(int a, int b) { x = a; y = b; }
* }
*/
public class Solution {
public int maxPoints(Point[] points) {
int maxValue=0;
/*for(int i=0;i<points.length-1;i++)*/
for (int i=0; i<(points.length-maxValue); i++){
Map<Double,Integer> map=new HashMap<Double,Integer>();
int same=0;
for(int j=i+1;j<points.length;j++){
double slop=0.0;
if(points[i].x==points[j].x && points[j].y==points[i].y){
same++;
continue;
}
else if(points[i].x==points[j].x){
slop=Double.MAX_VALUE;
}
else if(points[i].y==points[j].y){
slop=0;
}
else{
slop=new Double((double) (points[i].y-points[j].y) / (points[i].x-points[j].x) );
}
if(!map.containsKey(slop)) map.put(slop,1);
else map.put(slop,map.get(slop)+1);
}
maxValue=Math.max(maxValue,1+same+maxValue(map) );
}
return maxValue;
}
public int maxValue(Map<Double,Integer> map){
int max=0;
Iterator it=map.keySet().iterator();
while(it.hasNext()){
max=Math.max(max ,map.get(it.next()) );
}
return max;
}
}思路:这个代码存在很多不严谨之处。
569

被折叠的 条评论
为什么被折叠?



