python解数独（超级简单）

此代码增加了计时的功能，给出了解数独的用时。

# coding=UTF8
import time
class jieshudu():#定义解数独类
    t = time.perf_counter()
    def guize(board0,board):
        def isvaild(i,j):#设定数独的规则
            for m in range(9):
                if m!=i and board[m][j]==board[i][j]:#列不能重复
                    return False
            for n in range(9):
                if n!=j and board[i][n]==board[i][j]:#行不重复
                    return False
            for m in range(i//3*3,i//3*3+3):#宫里面不重复
                for n in range(j//3*3,j//3*3+3):
                    if m!=i and n!=j and board[m][n]==board[i][j]:
                        return False
            return True
        def f(a,b,board):#填数字进每个空格里面
            for i in range(a,9):
                for j in range(b,9):
                    if board[i][j]=='.':#找空格
                        for c in '123456789':