Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x.
You should preserve the original relative order of the nodes in each of the two partitions.
For example,
Given 1->4->3->2->5->2 and x = 3,
return 1->2->2->4->3->5.
class Solution {
public:
ListNode* partition(ListNode* head, int x) {
ListNode left(0), right(0);
ListNode *l = &left, *r = &right;
while(head){
ListNode* & ref = head->val < x ? l : r;
ref->next = head;
ref = ref->next;
head = head->next;
}
l->next = right.next;
r->next = NULL;
return left.next;
}
};
本文介绍了一种链表分区算法的实现方法,该算法能够确保所有小于给定值 x 的节点出现在大于等于 x 的节点之前,同时保持各分区内部节点原有的相对顺序。通过具体的代码示例展示了如何使用两个辅助链表来分别收集小于 x 和大于等于 x 的节点,最后将二者连接起来形成最终的分区链表。
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