首先介绍的是啤酒和尿布的故事(上网自查),这是学习关联规则必须知道的一个故事。
频繁项集,关联规则,支持度,置信度这四个概念贯穿Apriori算法的始终。
如果一个集合不是频繁相集,那它的超集比然也不是频繁相集。
机器学习实战例子:
#coding:utf-8
from numpy import *
def loadDataSet():
return[[1,3,4],[2,3,5],[1,2,3,5],[2,5]]
def createC1(dataSet):
c1 = []
for transaction in dataSet:
for item in transaction:
if not [item] in c1:
c1.append([item])
c1.sort()
return map(frozenset,c1)
>>> D=apriori.loadDataSet()
>>> C=apriori.createC1(D)
>>> print C
[frozenset([1]), frozenset([2]), frozenset([3]), frozenset([4]), frozenset([5])]
获得集合中组成元素
def scanD(D, Ck, minSupport):
ssCnt = {}
for tid in D:
for can in Ck:
if can.issubset(tid):
if not ssCnt.has_key(can): ssCnt[can]=1
else: ssCnt[can] += 1
numItems = float(len(D))
retList = []
supportData = {}
for key in ssCnt:
support = ssCnt[key]/numItems
if support >= minSupport:
retList.insert(0,key)
supportData[key] = support
return retList, supportData
def aprioriGen(Lk, k): #creates Ck 求两个集合的合并
retList = []
lenLk = len(Lk)
for i in range(lenLk):
for j in range(i+1, lenLk):
L1 = list(Lk[i])[:k-2]; L2 = list(Lk[j])[:k-2]
L1.sort(); L2.sort()
if L1==L2: #if first k-2 elements are equal
retList.append(Lk[i] | Lk[j]) #set union
return retList
def apriori(dataSet, minSupport = 0.5):
C1 = createC1(dataSet)
D = map(set, dataSet)
L1, supportData = scanD(D, C1, minSupport)
L = [L1]
k = 2
while (len(L[k-2]) > 0):
Ck = aprioriGen(L[k-2], k) #每次循环合并成两项集,三项集....
Lk, supK = scanD(D, Ck, minSupport)#scan DB to get Lk
supportData.update(supK)
L.append(Lk)
k += 1
return L, supportData
>>> L,suppData=apriori.apriori(D)
>>> print L
[[frozenset([1]), frozenset([3]), frozenset([2]), frozenset([5])], [frozenset([1, 3]), frozenset([2, 5]), frozenset([2, 3]), frozenset([3, 5])], [frozenset([2, 3, 5])], []]
>>> print suppData
{frozenset([5]): 0.75, frozenset([3]): 0.75, frozenset([2, 3, 5]): 0.5, frozenset([1, 2]): 0.25, frozenset([1, 5]): 0.25, frozenset([3, 5]): 0.5, frozenset([4]): 0.25, frozenset([2, 3]): 0.5, frozenset([2, 5]): 0.75, frozenset([1]): 0.5, frozenset([1, 3]): 0.5, frozenset([2]): 0.75}
def generateRules(L, supportData, minConf=0.7): #supportData is a dict coming from scanD
bigRuleList = []
for i in range(1, len(L)):#only get the sets with two or more items
for freqSet in L[i]:
H1 = [frozenset([item]) for item in freqSet]
if (i > 1):
rulesFromConseq(freqSet, H1, supportData, bigRuleList, minConf)
else:
calcConf(freqSet, H1, supportData, bigRuleList, minConf)
return bigRuleList
def calcConf(freqSet, H, supportData, brl, minConf=0.7):
prunedH = [] #create new list to return
for conseq in H:
conf = supportData[freqSet]/supportData[freqSet-conseq] #calc confidence
if conf >= minConf:
print freqSet-conseq,'-->',conseq,'conf:',conf
brl.append((freqSet-conseq, conseq, conf))
prunedH.append(conseq)
return prunedH
def rulesFromConseq(freqSet, H, supportData, brl, minConf=0.7):
print "#H#",H
m = len(H[0])
if (len(freqSet) > (m + 1)): #try further merging
Hmp1 = aprioriGen(H, m+1)#create Hm+1 new candidates
Hmp1 = calcConf(freqSet, Hmp1, supportData, brl, minConf)
if (len(Hmp1) > 1): #need at least two sets to merge
rulesFromConseq(freqSet, Hmp1, supportData, brl, minConf)
>>> rules=apriori.generateRules(L,suppData,minConf = 0.5)
frozenset([3]) --> frozenset([1]) conf: 0.666666666667
frozenset([1]) --> frozenset([3]) conf: 1.0
frozenset([5]) --> frozenset([2]) conf: 1.0
frozenset([2]) --> frozenset([5]) conf: 1.0
frozenset([3]) --> frozenset([2]) conf: 0.666666666667
frozenset([2]) --> frozenset([3]) conf: 0.666666666667
frozenset([5]) --> frozenset([3]) conf: 0.666666666667
frozenset([3]) --> frozenset([5]) conf: 0.666666666667
#H# [frozenset([2]), frozenset([3]), frozenset([5])]
frozenset([5]) --> frozenset([2, 3]) conf: 0.666666666667
frozenset([3]) --> frozenset([2, 5]) conf: 0.666666666667
frozenset([2]) --> frozenset([3, 5]) conf: 0.666666666667
#H# [frozenset([2, 3]), frozenset([2, 5]), frozenset([3, 5])]