Given a collection of numbers, return all possible permutations.
For example,
[1,2,3] have the following permutations:
[1,2,3], [1,3,2], [2,1,3], [2,3,1], [3,1,2],
and [3,2,1].
void get(vector<int> &num, int index, vector<vector<int>> &solution)
{
if(index >= num.size())
{
solution.push_back(num);
return;
}else
for(int i = index; i < num.size(); i++)
{
swap(num[index],num[i]);
get(num,index+1,solution);
swap(num[index],num[i]);
}
}
vector<vector<int>> permute(vector<int> &num) {
// Note: The Solution object is instantiated only once.
vector<vector<int>> solution;
if(num.size()<1)return solution;
get(num, 0, solution);
return solution;
}

本文提供了一种方法来生成给定数字集合的所有可能排列组合,包括示例和实现代码。
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