使用正则表达式生成匹配数组

 private List<Double> reg(string instr, string dw)
        {

            //生成list

            List<Double> list = new List<Double>();
            Regex regex = new Regex("(\\d+)(\\.(\\d+)?)?" + dw);
            MatchCollection matchs = regex.Matches(instr);
            foreach (Match match in matchs)
            {
                list.Add(Convert.ToDouble(match.Value.Substring(0, match.Value.IndexOf(dw))));

            }

            //将list的最大值和最小值放在最后和最前面的位置上；
            int listCount = list.Count;
            if (listCount <= 1)
                return list;
            else
            {
                Double max = -100.0, min = 100.0;
                for (int i = 0; i <= list.Count - 1; i++)
                {
                    if (i == 0)
                    {
                        max = min = list[0];
                    }

                    if (list[i] > max)
                    {
                        max = list[i];
                    }
                    if (list[i] < min)
                    {
                        min = list[i];
                    }

                }
                list[0] = min;
                list[listCount - 1] = max;
            }


            return list;
        }

转载于:https://www.cnblogs.com/huangbaoyu/archive/2008/02/22/1077554.html