Given an unsorted integer array, find the smallest missing positive integer.
Example 1:
Input: [1,2,0] Output: 3
Example 2:
Input: [3,4,-1,1] Output: 2
Example 3:
Input: [7,8,9,11,12] Output: 1
Note:
Your algorithm should run in O(n) time and uses constant extra space.
解答:
class Solution:
def firstMissingPositive(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
i = 0
length = len(nums)
while i < length:
if nums[i] == i + 1 or nums[i] > length or nums[i] <= 0:
i += 1
else:
index = nums[i] - 1
if nums[index] == nums[i]:
i += 1
continue
nums[i], nums[index] = nums[index], nums[i]
min = 1
i = 0
while i < length and nums[i] == i + 1 :
i += 1
return i + 1