1042 Shuffling Machine

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最新推荐文章于 2025-07-30 14:22:39 发布

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该博客介绍了一个模拟自动洗牌机器的算法问题，输入是一个洗牌规则和重复次数，输出是经过多次洗牌后的扑克牌顺序。题目要求根据给定的初始扑克牌顺序和洗牌顺序，使用C++实现洗牌过程，并打印最终结果。解决方案是通过两个数组分别存储原始顺序和洗牌结果，然后根据洗牌规则进行操作。

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Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techniques are seen as weak, and in order to avoid "inside jobs" where employees collaborate with gamblers by performing inadequate shuffles, many casinos employ automatic shuffling machines. Your task is to simulate a shuffling machine.

The machine shuffles a deck of 54 cards according to a given random order and repeats for a given number of times. It is assumed that the initial status of a card deck is in the following order:

S1, S2, ..., S13, 
H1, H2, ..., H13, 
C1, C2, ..., C13, 
D1, D2, ..., D13, 
J1, J2

where "S" stands for "Spade", "H" for "Heart", "C" for "Club", "D" for "Diamond", and "J" for "Joker". A given order is a permutation of distinct integers in [1, 54]. If the number at the i-th position is j, it means to move the card from position i to position j. For example, suppose we only have 5 cards: S3, H5, C1, D13 and J2. Given a shuffling order {4, 2, 5, 3, 1}, the result will be: J2, H5, D13, S3, C1. If we are to repeat the shuffling again, the result will be: C1, H5, S3, J2, D13.

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer K (≤20) which is the number of repeat times. Then the next line contains the given order. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print the shuffling results in one line. All the cards are separated by a space, and there must be no extra space at the end of the line.

Sample Input:

2
36 52 37 38 3 39 40 53 54 41 11 12 13 42 43 44 2 4 23 24 25 26 27 6 7 8 48 49 50 51 9 10 14 15 16 5 17 18 19 1 20 21 22 28 29 30 31 32 33 34 35 45 46 47

Sample Output:

S7 C11 C10 C12 S1 H7 H8 H9 D8 D9 S11 S12 S13 D10 D11 D12 S3 S4 S6 S10 H1 H2 C13 D2 D3 D4 H6 H3 D13 J1 J2 C1 C2 C3 C4 D1 S5 H5 H11 H12 C6 C7 C8 C9 S2 S8 S9 H10 D5 D6 D7 H4 H13 C5

题目大意

给你一个洗牌规则，求一套未打乱的扑克牌，按照上述方式洗牌后的牌况

思路

开俩个数组，一个读入，一个记录结果即可

C/C++

#include<bits/stdc++.h>
using namespace std;
string nums[55],result[55];
int N,key[55];
void OP(int now,int end,int deep);
int main()
{
    for(int z=1;z<=13;z++) nums[z] = "S" + to_string(z);
    for(int z=1;z<=13;z++) nums[z+13] = "H" + to_string(z);
    for(int z=1;z<=13;z++) nums[z+26] = "C" + to_string(z);
    for(int z=1;z<=13;z++) nums[z+39] = "D" + to_string(z);
    nums[53] = "J1",nums[54] = "J2";
    cin >> N;
    for(int z=1;z<=54;z++) cin >> key[z];
    for(int z=1;z<=54;z++) OP(z,key[z],1);
    cout << result[1];
    for(int z=2;z<=54;z++) cout << " " << result[z];
    return 0;
}
void OP(int now,int end,int deep)
{
    if(deep==N) result[end] = nums[now];
    else OP(now,key[end],deep+1);
}