dashuxiaoai52613的专栏

Agri-NetTime Limit: 1000ms Memory limit: 10000kB 题目描述 Farmer John has been elected mayor of his town! One of his campaign promises was to bring internet connectivity to all farms in the area. He needs

 //题意：只有在点S或点A可以分，求从点S到达所有点A的最少步数。可以用BFS+Prim实现，BFS用来求得任意两点间////可达所需的最少步数，从而能构成一张图，两点间的权值就是BFS求得的最少步数。然后用Prim求解。  #include#include#include#define MAXX 0x7fffffffusing namespace std;

Agri-NetTime Limit: 1000MS Memory Limit: 10000KTotal Submissions: 14112 Accepted: 5700DescriptionFarmer John has been elected mayor of his town! One of his campaign

<br />相信自己的模板<br />#define MAX_VERTEX_NUM 101 #define INFINITY 0x11111111 typedef struct{ int val; //int info; }ArcType,ArcMatrix[MAX_VERTEX_NUM][MAX_VERTEX_NUM]; typedef struct{ int vexnum; VertexType vexs[MAX_VERTEX_NUM]; A

<br />// Prim.cpp : Defines the entry point for the console application. // #define MAX_VERTEX_NUM 101 #define INFINITY 0x11111111 #define TRUE 1 #define FALSE 0 typedef struct{ //int info; }VertexType; typedef struct{ int val;

<br />#define MAX_VERTEX_NUM 505 #define INFINITY 0x11111111 typedef struct{ //int info; }VertexType; typedef struct{ int val; //int info; }ArcType,ArcMatrix[MAX_VERTEX_NUM][MAX_VERTEX_NUM]; typedef struct{ int vexnum; Vertex

完整自己写

0xfffffff最大double