package singleTon;
public class Algorilthm01 {
//冒泡排序
public static void main(String[] args) {
int[] zz = {9,44,541,12,32,45,64,74,751,254,235,4};
for (int i = 0; i < zz.length-1; i++) {//需要查找zz.length-1就可以排序完成
for (int j = 0; j < zz.length-i-1; j++) { //每次查找的范围都是随着i++而缩小的
if (zz[j]>zz[j+1]) {
int temp;
temp=zz[j];
zz[j]=zz[j+1];
zz[j+1]=temp;
}
}
System.out.println("第"+(i+1)+"次查找该数组");
for (int a = 0; a < zz.length; a++) {
System.out.println(zz[a]);
}
}
for (int a = 0; a < zz.length; a++) {
System.out.println(zz[a]);
}
}
}
排序-冒泡排序简单实现
最新推荐文章于 2022-01-21 02:07:34 发布