杭电acm1062 Text Reverse

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cwhong723

最新推荐文章于 2021-07-13 21:21:25 发布

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本文链接：https://blog.youkuaiyun.com/cwhong_723/article/details/78845172

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本文介绍了一个ACM竞赛题目“TextReverse”的解决方案，该题目要求反转输入文本中的每个单词。文章提供了一段Java代码实现，通过读取多组测试数据并输出反转后的单词来解决问题。

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Text Reverse

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 34449 Accepted Submission(s): 13532

Problem Description

Ignatius likes to write words in reverse way. Given a single line of text which is written by Ignatius, you should reverse all the words and then output them.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains a single line with several words. There will be at most 1000 characters in a line.

Output

For each test case, you should output the text which is processed.

Sample Input

  
  
   
   3
olleh !dlrow
m'I morf .udh
I ekil .mca

Sample Output

  
  
   
   hello world!
I'm from hdu.
I like acm.


   
   
    
    
     
     Hint
    
    

    
    Remember to use getchar() to read '\n' after the interger T, then you may use gets() to read a line and process it.
    
    

    
    //简单的字符串处理
    
    

    
    
    
    /**
 * date:2017.11.12
 * author:孟小德
 * function:acm试题1062
 *  Text Reverse 文本倒置
 */



import java.util.*;

public class acm1062
{
    public static void main(String[] args)
    {
        Scanner input = new Scanner(System.in);

        int num = input.nextInt();
        input.nextLine();

        String[] string = new String[num];
        for (int i=0;i<num;i++)
        {
            string[i] = input.nextLine();
        }

        String[] result = new String[num];
        for (int i=0;i<num;i++)
        {

            String[] str = string[i].split(" ");    //分割字符串

            result[i] = stringReverse(str[0]);
            for (int j = 1;j<str.length;j++)
            {
                result[i] = result[i] + " " + stringReverse(str[j]);
            }

            //末尾空格加上
            int n = string[i].length() - result[i].length();
            for (int j = 0;j<n;j++)
            {
                result[i] += " ";
            }

        }

        for (int i = 0;i<num;i++)
        {
            System.out.println(result[i]);
        }
    }

    //翻转单词字母
    public static String stringReverse(String str)
    {

        if (str.equals(""))
        {
            return "";
        }
        else
        {
            String string = String.valueOf(str.charAt(str.length()-1));
            for (int i=str.length()-2;i>=0;i--)
            {
                string += String.valueOf(str.charAt(i));

            }

            return string;
        }
    }
}