cunane的博客

链接：Make bricks问题 思路：先尽可能多地使用大的，再使用小的 1）用了多少块大的：min(big, goal / 5) 2）还需要多少块小的：goal - 5 * min(big, goal / 5) def make_bricks(small, big, goal): if goal / 5 <= big: return goal % 5 <= sm...

问题描述：squareUp问题 Given n&gt;=0, create an array length n*n with the following pattern, shown here for n=3 : {0, 0, 1,    0, 2, 1,    3, 2, 1} (spaces added to show the 3 groups). squareUp(3...