Given an array of words and a length L, format the text such that each line has exactly L characters and is fully (left and right) justified.
You should pack your words in a greedy approach; that is, pack as many words as you can in each line. Pad extra spaces ' ' when necessary so that each line has exactlyL characters.
Extra spaces between words should be distributed as evenly as possible. If the number of spaces on a line do not divide evenly between words, the empty slots on the left will be assigned more spaces than the slots on the right.
For the last line of text, it should be left justified and no extra space is inserted between words.
For example,
words: ["This", "is", "an", "example", "of", "text", "justification."]
L: 16.
Return the formatted lines as:
[ "This is an", "example of text", "justification. " ]
Note: Each word is guaranteed not to exceed L in length.
/*
这种题目,没有什么算法
就是,try-fail 各种test
其实还是没看懂题目的赶脚,so look below
Input: ["Listen","to","many,","speak","to","a","few."], 6
Output: ["Listen","to","many,","speak","to a","few. "]
Expected: ["Listen","to ","many, ","speak ","to a","few. "]
*/
public class Solution {
public List<String> fullJustify(String[] words, int maxWidth) {
//maxWidth >= words[i].length
int lenWords = words.length;
List<String> list = new ArrayList<String>();
if(words.length == 1 && words[0].isEmpty()) {
StringBuilder sb = new StringBuilder();
for(int i = 0;i<maxWidth;i++)
sb.append(" ");
sb.append("");
list.add(sb.toString());
return list;
}
for(int item = 0;item<lenWords;) {
int lenStr = 0;
StringBuilder sb = new StringBuilder();
int start = item,end = 0;
while(item<lenWords && lenStr < maxWidth) {
lenStr += words[item].length()+1;
if(lenStr > maxWidth+1) {
lenStr -= words[item].length()+1;
break;
}
item++;
}
end = item - 1;
int len = 0,lenRemainder = 0;
if(end != start) {
len = (maxWidth-lenStr+1)/(end-start);
lenRemainder = (maxWidth-lenStr+1)%(end-start);
}
if(end == words.length - 1) {
for(int j = start;j<end;j++)
sb.append(words[j]+" ");
sb.append(words[end]);
} else {
for(int j = start;j<end;j++) {
sb.append(words[j]+" ");
for(int i = 0;i<len;i++) {
sb.append(' ');
}
if(lenRemainder-- > 0) {
sb.append(' ');
}
}
sb.append(words[end]);
}
int lenSb = sb.length();
while(lenSb++ < maxWidth)
sb.append(' ');
list.add(sb.toString());
}
return list;
}
}
本文详细介绍了如何使用编程方法对文本进行优化排列与格式化,重点探讨了如何根据给定长度将一系列单词排列成多行,并确保每行达到指定宽度的同时实现左右对齐。通过实例演示了不同场景下的文字排列策略,包括空格分配、对齐方式的选择以及特殊处理如最后一行的左对齐等。

被折叠的 条评论
为什么被折叠?



