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题目:36. 有效的数独判断一个 9x9 的数独是否有效。只需要根据以下规则,验证已经填入的数字是否有效即可。
数字 1-9 在每一行只能出现一次。
数字 1-9 在每一列只能出现一次。
数字 1-9 在每一个以粗实线分隔的 3x3 宫内只能出现一次。
上图是一个部分填充的有效的数独。
数独部分空格内已填入了数字,空白格用 ‘.’ 表示。 -
示例 1:
输入:
[
[“5”,“3”,".",".",“7”,".",".",".","."],
[“6”,".",".",“1”,“9”,“5”,".",".","."],
[".",“9”,“8”,".",".",".",".",“6”,"."],
[“8”,".",".",".",“6”,".",".",".",“3”],
[“4”,".",".",“8”,".",“3”,".",".",“1”],
[“7”,".",".",".",“2”,".",".",".",“6”],
[".",“6”,".",".",".",".",“2”,“8”,"."],
[".",".",".",“4”,“1”,“9”,".",".",“5”],
[".",".",".",".",“8”,".",".",“7”,“9”]
]
输出: true -
示例 2:
输入:
[
[“8”,“3”,".",".",“7”,".",".",".","."],
[“6”,".",".",“1”,“9”,“5”,".",".","."],
[".",“9”,“8”,".",".",".",".",“6”,"."],
[“8”,".",".",".",“6”,".",".",".",“3”],
[“4”,".",".",“8”,".",“3”,".",".",“1”],
[“7”,".",".",".",“2”,".",".",".",“6”],
[".",“6”,".",".",".",".",“2”,“8”,"."],
[".",".",".",“4”,“1”,“9”,".",".",“5”],
[".",".",".",".",“8”,".",".",“7”,“9”]
]
输出: false
解释: 除了第一行的第一个数字从 5 改为 8 以外,空格内其他数字均与 示例1 相同。
但由于位于左上角的 3x3 宫内有两个 8 存在, 因此这个数独是无效的。 -
说明:
一个有效的数独(部分已被填充)不一定是可解的。
只需要根据以上规则,验证已经填入的数字是否有效即可。
给定数独序列只包含数字 1-9 和字符 ‘.’ 。
给定数独永远是 9x9 形式的。 -
思路1
public boolean isValidSudoku(char[][] board) {
for (int i = 0; i < 9; i++) {
//检查列
if (!isParticallyValid(board, 0, 8, i, i)) {
return false;
}
//检查行
if (!isParticallyValid(board, i, i, 0, 8)) {
return false;
}
}
//检查块
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
if (!isParticallyValid(board, i * 3, i * 3 + 2, j * 3, j * 3 + 2))
return false;
}
}
return true;
}
//把要检查的值存入到set中,每次向set中添加值的时候,如果失败则证明该值已经存在
private boolean isParticallyValid(char[][] board, int x1, int x2, int y1, int y2) {
Set<Character> set = new HashSet<>();
for (int i = x1; i <= x2; i++) {
for (int j = y1; j <= y2; j++) {
if (board[i][j] != '.' && !set.add(board[i][j]))
return false;
}
}
return true;
}
- 思路2
//set中存放所有字符的3个属性:行、列、和块的位置;向set中添加属性的时候,添加失败则返回false;如果全部添加成功则返回true
public boolean isValidSudoku(char[][] board) {
Set<String> set = new HashSet<>();
for (int i = 0; i < 9; i++) {
for (int j = 0; j < 9; j++) {
Character c = board[i][j];
if (c != '.') {
if (!set.add(c + "in row" + i)
|| !set.add(c + "in col" + j)
|| !set.add(c + "in block" + i / 3 + "-" + j / 3))
return false;
}
}
}
return true;
}