<cf>System of Equations(水题)

本文介绍了一个关于寻找整数解的方程组问题,通过给定的参数n和m,利用编程方法找到满足条件的整数对(a, b),并对样例进行了说明。
System of Equations
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

Furik loves math lessons very much, so he doesn't attend them, unlike Rubik. But now Furik wants to get a good mark for math. For that Ms. Ivanova, his math teacher, gave him a new task. Furik solved the task immediately. Can you?

You are given a system of equations:

You should count, how many there are pairs of integers (a, b) (0 ≤ a, b) which satisfy the system.

Input

A single line contains two integers n, m (1 ≤ n, m ≤ 1000) — the parameters of the system. The numbers on the line are separated by a space.

Output

On a single line print the answer to the problem.

Sample test(s)
input
9 3
output
1
input
14 28
output
1
input
4 20
output
0
Note

In the first sample the suitable pair is integers (3, 0). In the second sample the suitable pair is integers(3, 5). In the third sample there is no suitable pair.

#include <stdio.h>
int main()
{
    int n,m;
    int cnt;
    while(scanf("%d%d",&n,&m)!=EOF)
   {
        cnt=0;
        for(int i=0;i*i<=n;i++)
        {
            double j=n-i*i;
            if((int)j==j && j*j+i==m)
                cnt++;
        }
        printf("%d\n",cnt);
   }
   return 0;
}


<SW.Blocks.CompileUnit ID="48" CompositionName="CompileUnits"> <AttributeList> <NetworkSource><FlgNet xmlns="http://www.siemens.com/automation/Openness/SW/NetworkSource/FlgNet/v5"> <Parts> <Access Scope="LiteralConstant" UId="21"> <Constant> <ConstantType>Bool</ConstantType> <ConstantValue>TRUE</ConstantValue> </Constant> </Access> <Access Scope="GlobalVariable" UId="22"> <Symbol> <Component Name="_+334+031+FD01" /> <Component Name="=M1-MBB" /> <Component Name="SetIntlkOK" /> </Symbol> </Access> <Part Name="Coil" UId="23" /> </Parts> <Wires> <Wire UId="24"> <IdentCon UId="21" /> <NameCon UId="23" Name="in" /> </Wire> <Wire UId="25"> <IdentCon UId="22" /> <NameCon UId="23" Name="operand" /> </Wire> </Wires> </FlgNet></NetworkSource> <ProgrammingLanguage>FBD</ProgrammingLanguage> </AttributeList> <ObjectList> <MultilingualText ID="49" CompositionName="Comment"> <ObjectList> <MultilingualTextItem ID="4A" CompositionName="Items"> <AttributeList> <Culture>en-GB</Culture> <Text>Interlock for Reset Movement</Text> </AttributeList> </MultilingualTextItem> <MultilingualTextItem ID="4B" CompositionName="Items"> <AttributeList> <Culture>nl-BE</Culture> <Text>Interlock for Reset Movement</Text> </AttributeList> </MultilingualTextItem> <MultilingualTextItem ID="4C" CompositionName="Items"> <AttributeList> <Culture>sv-SE</Culture> <Text>Interlock for Reset Movement</Text> </AttributeList> </MultilingualTextItem> <MultilingualTextItem ID="4D" CompositionName="Items"> <AttributeList> <Culture>zh-CN</Culture> <Text>Interlock for Reset Movement</Text> </AttributeList> </MultilingualTextItem> </ObjectList> </MultilingualText> <MultilingualText ID="4E" CompositionName="Title"> <ObjectList> <MultilingualTextItem ID="4F" CompositionName="Items"> <AttributeList> <Culture>en-GB</Culture> <Text>**** 5.1 - Equations - Interlock **** =M1-MBB SetIntlkOK</Text> </AttributeList> </MultilingualTextItem> <MultilingualTextItem ID="50" CompositionName="Items"> <AttributeList> <Culture>nl-BE</Culture> <Text>**** 5.1 - Equations - Interlock **** =M1-MBB SetIntlkOK</Text> </AttributeList> </MultilingualTextItem> <MultilingualTextItem ID="51" CompositionName="Items"> <AttributeList> <Culture>sv-SE</Culture> <Text>**** 5.1 - Equations - Interlock **** =M1-MBB SetIntlkOK</Text> </AttributeList> </MultilingualTextItem> <MultilingualTextItem ID="52" CompositionName="Items"> <AttributeList> <Culture>zh-CN</Culture> <Text>**** 5.1 - Equations - Interlock **** =M1-MBB SetIntlkOK</Text> </AttributeList> </MultilingualTextItem> </ObjectList> </MultilingualText> </ObjectList> </SW.Blocks.CompileUnit>把这个XML转换成一个方法,+334+031+FD01,可以由,Zone,workstation,FD,三个string数据替换,
最新发布
09-08
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