Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2
, return 1->2
.
Given 1->1->2->3->3
, return 1->2->3
.
思路:双指针
p从头开始遍历,q为第一个值不等于p的结点,删除p到q之间的结点
代码:
ListNode *deleteDuplicates(ListNode *head) {
if(head == NULL)
return head;
ListNode *p=head;
ListNode *q=p->next;
if(q == NULL)
return head;
while(p!=NULL && q!=NULL)
{
if(q->val == p->val)
{
q=q->next;
}
else
{
p->next=q;
p=q;
q=p->next;
}
}
if(q==NULL && p!=NULL)
{
p->next=NULL;
}
return head;
}