杭电ACM 1096 简单求和

最新推荐文章于 2021-11-05 11:33:57 发布

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本文介绍了一个计算整数之和的算法实践，包括输入格式、输出要求及样例代码，涵盖Java和C++实现。

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A+B for Input-Output Practice (VIII)

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 101145 Accepted Submission(s): 31156

Problem Description

Your task is to calculate the sum of some integers.

Input

Input contains an integer N in the first line, and then N lines follow. Each line starts with a integer M, and then M integers follow in the same line.

Output

For each group of input integers you should output their sum in one line, and you must note that there is a blank line between outputs.

Sample Input

  
   3
4 1 2 3 4
5 1 2 3 4 5
3 1 2 3

Sample Output

题目链接：http://acm.hdu.edu.cn/showproblem.php?pid=1096

java 代码：

import java.util.Scanner;

public class Main {
	public static void main(String args[]){
		Scanner reader = new Scanner(System.in);
		int n,m,sum,i;
		n = reader.nextInt();
		while(n > 0){
			m = reader.nextInt();
			sum = 0;
			for(i = 0; i<m; i++){
				sum += reader.nextInt();
			}
			System.out.println(sum);
			n--;
			if(n != 0){
				System.out.println();
			}
		}
		reader.close();
	}
}

c++代码：

#include<stdio.h>
int main(){
	int n,m,k,i,sum;
	scanf("%d",&n);
	while(n--){
		scanf("%d",&m);
		sum = 0;
		for(i = 0; i<m; i++){
			scanf("%d",&k);
			sum += k;
		}
		printf("%d\n",sum);
		if(n != 0){
			printf("\n");
		}
	}
	return 0;
}