HDU 1596 find the safest road

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传送门

[0,1]区间乘积最长路。和这个类似,不过这道题没有大于1的边,所以没有“负环”(在一个环上走不会越来越大)。

这道题已经给了邻接矩阵(所以连初始化都不用了),按有向图算,不连通的边都给了0。所以最后查询的时候还是0就意味着不连通。

这道题用不着考虑floyd里面那三个相不相等。


#include <cstdio>
#include <iostream>
#include <algorithm>
#include <vector>
#include <cstring>
#include <string>
#include <queue>
using namespace std;

const double INF = 1e9;             // double...然而没用到
const int MAX = 1001;
int N, Q;
double g[MAX][MAX];

void floyd()
{
	for (int k = 1; k <= N; k++)
	{
		for (int i = 1; i <= N; i++)
		{
			for (int j = 1; j <= N; j++)
			{
				if (g[i][k] != 0.0 && g[k][j] != 0.0 && g[i][j] < g[i][k] * g[k][j])
					g[i][j] = g[i][k] * g[k][j];
			}
		}
	}
}

int main()
{
	int a, b;
	for (; ~scanf("%d", &N);)
	{
		for (int i = 1; i <= N; i++)
			for (int j = 1; j <= N; j++)
				scanf("%lf", &g[i][j]);
		floyd();
		scanf("%d", &Q);
		for (; Q--;)
		{
			scanf("%d%d", &a, &b);
			if (g[a][b] == 0.0)
				printf("What a pity!\n");
			else printf("%.3lf\n", g[a][b]);
		}
	}

	return 0;
}
openharmony之启动恢复子系统详解 需求: 添加一个名为my_service的自定义服务步骤1: 创建服务配置],],"env": [步骤2: 添加到主配置],"jobs": ["cmds": [步骤3: 验证配置# ✅ 检查配置格式 jq . /system/etc/init/my_service.cfg # 🔄 重新加载配置 begetctl reload # 📊 验证服务状态 begetctl dump_service my_serviceOpenHarmony init进程的完整生命周期。🔄 三阶段启动模型⚙️ 配置体系。 阅读详情

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